#T95. 二分法求函数的零点

二分法求函数的零点

Description

There is a function: f(x)=x515x4+85x3225x2+274x121f(x)=x^5-15x^4+85x^3-225x^2+274x-121. It is known that f(1.5)>0f(1.5)>0, f(2.4)<0f(2.4)< 0, and the equation f(x)=0f(x)=0 has exactly one root in the interval [1.5,2.41.5,2.4]. Please use the bisection method to find this root.

Input Format

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Output Format

The root of the equation in the interval [1.5,2.41.5,2.4]. The result should be rounded to 6 decimal places.

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