#T627. 查找元素
查找元素
Description
Try to write an algorithm that searches for a number in a singly linked list with a head node.
If found, the function should return the address (position i [1~n]) of the number in the list;
If not found, the function should return 0.
Input Format
First line: the original sequence;
Second line: the number to search for
Output Format
If found, output the position of the number in the sequence (the first position is output as 1, and so on);
If not found, output 0
```input1 2 3 4 5 6 7 8 9 5 ``` ```output1 4 ``` ## HintUse the linear list method
No solution available yet. AC program
Source
CodesOnline