Description

In Tsinghua University's campus, life would be very inconvenient without a bicycle when attending classes or handling errands. However, in reality, biking isn't always faster for every task because it involves finding a bike, unlocking it, parking it, and locking it again, which takes some time.

Assume the following:

• The time to find a bike, unlock it, and mount it is 27 seconds.
• The time to park and lock the bike is 23 seconds.
• Walking speed is 1.2 meters per second.
• Biking speed is 3.0 meters per second.

Determine whether biking or walking is faster for different distances.

• If biking is faster, output "Bike".
• If walking is faster, output "Walk".
• If they take the same time, output "All".

Input Format

The input consists of a single line containing an integer representing the distance (in meters) for the errand.

Output Format

Output a single line:

• "Bike" if biking is faster,
• "Walk" if walking is faster,
• "All" if they take the same time.

Example

Input:

120  

Output:

Bike  

Explanation:

• Biking time = 27 (prep) + 23 (parking) + (120 / 3.0) = 27 + 23 + 40 = 90 seconds.
• Walking time = 120 / 1.2 = 100 seconds.
  Since biking is faster, the output is "Bike".

Constraints

• The input distance is a positive integer.

Solution Approach

1. Calculate total biking time:
   • Prep time (27s) + Parking time (23s) + (Distance / 3.0).
2. Calculate walking time:
   • Distance / 1.2.
3. Compare the two times and output the result accordingly.

This problem requires careful handling of floating-point arithmetic to ensure accurate comparisons.

120

Bike

翻译结果

CodesOnline

（注：由于"CodesOnline"是一个专有名词或品牌名称，通常保持原样不翻译。如果上下文需要解释，可以补充说明其含义，例如："CodesOnline（代码在线）"。此处根据要求直接保留原文格式。）

保留markdown格式的翻译示例：

## Source  

CodesOnline  

（若需进一步调整或补充说明请告知。）