2 solutions

  • 3
    @ 2025-6-7 9:07:44

    Peter is Strong!!!

    Tymon is Strong!!!

    Nathan is Strong!!!

    Adam is the strongest!!!!!

    #include<iostream>
    #include<string.h>
    using namespace std;
    int main()
    {
    	string a;
    	getline(cin, a);
    	for(int i=0;i<a.size();i++)
    	{
    		if(a[i] >= 'a' && a[i] <= 'y')
    		{
    			a[i]+=1;
    		}
    		else if(a[i] >= 'A' && a[i] <= 'Y')
    		{
    			a[i]+=1;
    		}
    		else if(a[i]== 'z')
    		{
    			a[i]='a';
    		}
    		else if(a[i] == 'Z')
    		{
    			a[i]='A';
    		}
    	}
    	cout << a;
     }
     
    
    • 1
      @ 2025-6-7 9:31:52
      #include<iostream>
      using namespace std;
      int main(){
      	string s;
      	getline(cin,s);
      	for(int i=0;i<s.size();i++){
      		if(s[i]>='A' and s[i]<='Y')
      		s[i]++;
      		else if (s[i]>='a'and s[i]<='y')
      		s[i]++;
      		else if (s[i]=='Z'or s[i]=='z')
      		s[i]-=25;
      }
      	cout<<s;
      	return 0;
      }
      #include<iostream>
      #include<string>
      using namespace std;
      int main(){
      	string s1,s2;
      	cin>>s1>>s2;
      	int n=s1.size();
      	int a[n]={0},b[n]={0},c[n+1]={0};
      	for(int i=0;i<s1.size();i++) a[i]=s1[s1.size()-i-1]-48;
      	for(int i=0;i<s2.size();i++) b[i]=s2[s2.size()-i-1]-48;
      	for(int i=0;i<n;i++)
      	{
      		if(c[i]+a[i]+b[i]<10) c[i]=c[i]+a[i]+b[i];
      		else{
      			c[i]=(c[i]+a[i]+b[i])%10;
      			c[i+1]++;
      		}
      	}
      	if(c[n]==1) cout<<1;
      	for(int i=n-1;i>=0;i--) cout<<c[i];
      	return 0; 
      }
      //Adam is strong
      //Peter is stronger
      //Hank is even more strong
      //Mr. Raviola is the strongest
      
      • 1

      Information

      ID
      1928
      Time
      1000ms
      Memory
      64MiB
      Difficulty
      8
      Tags
      # Submissions
      17
      Accepted
      7
      Uploaded By