1 solutions
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1
#include<bits/stdc++.h> using namespace std; int main(){ string s; cin>>s; long long a=1; long long b=1; for(int i=0;i<=s.size();i++){ a *= s[i]-'A'+1; } a %= 47; cin>>s; for(int i=0;i<=s.size();i++){ b *= s[i]-'A'+1; } b %= 47; if(a == b) cout<<"GO"; else cout<<"STAY"; return 0; }
Information
- ID
- 1978
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- # Submissions
- 26
- Accepted
- 8
- Uploaded By